Assert statements should not cause side effects. Line 22 changes the value of z if the assert statement is false.

Option A is fine; a second expression in an assert statement is not required.

Option B is fine because it is perfectly acceptable to call a method with the second expression of an assert statement.

Option C is fine because it is proper to call an assert statement conditionally.

Option D is correct. Compilation fails because of an unreachable statement at line 14. It is a compile-time error if a statement cannot be executed because it is unreachable. The question is now, why is line 20 unreachable? If it is because of the assert then surely line 6 would also be unreachable. The answer must be something other than assert.

Examine the following:

A while statement can complete normally if and only if at least one of the following is true:

- The while statement is reachable and the condition expression is not a constant expression with value true.

-There is a reachable break statement that exits the while statement.

The while statement at line 11 is infinite and there is no break statement therefore line 14 is unreachable. You can test this with the following code:

public class Test80 
{ 
    public void foo() 
    {
        assert false; 
        assert false; 
    } 
    public void bar()
    {
        while(true)
        {
            assert false; 
            break; 
        } 
        assert false;  
    } 
}